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(F)=9F^2-54F-144
We move all terms to the left:
(F)-(9F^2-54F-144)=0
We get rid of parentheses
-9F^2+F+54F+144=0
We add all the numbers together, and all the variables
-9F^2+55F+144=0
a = -9; b = 55; c = +144;
Δ = b2-4ac
Δ = 552-4·(-9)·144
Δ = 8209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{8209}}{2*-9}=\frac{-55-\sqrt{8209}}{-18} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{8209}}{2*-9}=\frac{-55+\sqrt{8209}}{-18} $
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